[衡水金卷]2026届高三年级3月份学情诊断(广东省)生物试题

[衡水金卷]2026届高三年级3月份学情诊断(广东省)生物试题于2026-03-04发布，目前已经汇总了[衡水金卷]2026届高三年级3月份学情诊断(广东省)生物试题的各科答案和试卷，更多试卷答案请关注本网站。

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[衡水金卷]2026届高三年级3月份学情诊断(广东省)地理试题

[衡水金卷]2026届高三年级3月份学情诊断(广东省)生物试题

After that, we went to the Great Wall, the 61.___________ wall in the world. There were many people on the Great Wall, 62.___________ it was very crowded. We also met many people from different 63.___________. They said the Great Wall was so fantastic.
We took quite a lot of photos on the wall and it took 64.___________ about four hours to get to the top. Then, we had our lunch on the Great Wall. Later, it started to rain 65.___________ on our way back in the afternoon. Each of us didn’t take 66.___________ umbrella. We had to 67.___________ a long time for the bus. It was almost eight in the evening when we came back to our hotel. We were all wet. My mother was tired. She felt 68.___________ because of the rain.
But it was sunny the next day. We planned 69.___________ the Beijing Zoo. We were so happy to hear the tickets that day were free. We spent three hours in the zoo 70.___________ different kinds of animals. In the afternoon, we started to return.
Our trip was short but I never forgot it.
五、补全对话。(有两项多余)（每小题1分，共5分）
A: Hi, John! Your father told me you had a trip last Saturday. 71.______
B: I went to Beijing with my uncle.

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(2)如图乙所示,把两个质量相等的小钢球,从斜面的同一高度由静止同时释放,观察到两球在水平面相遇,这说明平抛运动在水平方向上做匀速直线运动.
(3)由图丙可知,小球在竖直方向上有Δh=5L-3L=gT2,解得T== s=0.1 s,照相机拍摄时每隔0.1 s曝光一次.小球在水平方向有Δx=v0T=3L,v0== m/s=1.47 m/s.
5.(1)BC　(2)1.0　2.2
[解析] (1)只要从同一位置静止释放小球,小球在运动中所受摩擦力每次都相同,斜槽轨道是否光滑,不影响小球抛出时的初速度是否相同,故A错误;为了保证小球做平抛运动,斜槽末端必须水平,故B正确;小球运动时挡板及白纸应保持竖直,保证小球竖直方向自由落体,故C正确;每次必须从斜槽上同一位置由静止释放小球,保持每次抛出的初速度相同,保证小球每次的轨迹都一样,故D错误.
(2)由表可得,1到2和2到3因两段对应的水平距离相等,故两段运动的时间相等,相同的时间段内,竖直位移分别为h1=15 cm和h2=25 cm,故在竖直方向由Δh=gt2可得t== s=0.1 s,水平速度v=v0== m/s=1.0 m/s.2点的竖直分速度为vy2== m/s=2 m/s,2点的速度为v2== m/s≈2.2 m/s.
6.(1)A　(2)①不是　②0.05　③0.75　④1
[解析] (1)该实验要求斜槽轨道有一定的倾角,但末端必须保持水平,以确保小球初速度水平,故A正确;由于要多次描点画同一运动轨迹,因此必须每次都在同一位置由静止释放小球,以确保小球初速度相同,斜槽轨道光滑与否,不会影响“确保小球初速度相同”,故B错误;由于要多次描点画同一运动轨迹,因此必须每次都在同一位置由静止释放小球,以确保小球初速度相同,故C错误;描点法描绘运动轨迹时,应将各点用平滑的曲线连接,不能用折线或直线连接,故D错误.

[衡水金卷]2026届高三年级3月份学情诊断(广东省)化学答案